If filtration provides 1 HVL of attenuation, the beam intensity is reduced to what fraction of the original?

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Multiple Choice

If filtration provides 1 HVL of attenuation, the beam intensity is reduced to what fraction of the original?

Explanation:
The HVL is the thickness of material that cuts the beam’s intensity in half. So when filtration provides 1 HVL, the beam intensity is reduced to half of the original value. In fractional terms, that’s 1/2. If you added another HVL, it would halve again (1/4 with two HVLs, 1/8 with three HVLs), and so on.

The HVL is the thickness of material that cuts the beam’s intensity in half. So when filtration provides 1 HVL, the beam intensity is reduced to half of the original value. In fractional terms, that’s 1/2. If you added another HVL, it would halve again (1/4 with two HVLs, 1/8 with three HVLs), and so on.

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